endobj 14 0 obj /Border [0 0 0] 581 Try to answer all the questions marked (a), (b), etc... 6. /URI (http://www.pdffactory.com) << /H /I For each child it is equally likely to be a boy or a girl. Originally used for a GCSE Higher tier set. ������8�)2L�|�G��&����� ���z�)YF�G�R�/@���O�+�9��v�v�. /F2 8 0 R endobj << /Subtype /Link /Rect [262.08 20.64 369.36 9.36] Œ†Ùr$ØàOÃaE‰ÿ¹R¢Dİ¥²„Ù|›}‡ÙëhŒsÜŒH/~‚J�C¢›¬çõÒÒ«WCXóí‘g7w¨BHÃkï‘¢„qnaMàÛ.kĞ9sf¼¡.„Ò8$»õ2PÔ™Ñ&a‰4Âü_Âbµ3�%§DËÍúí /ProcSet [/PDF/Text] >> /A 13 0 R PROBABILITY & TREE DIAGRAMS Materials required for examination Items included with question papers Ruler graduated in centimetres and Nil millimetres, protractor, compasses, pen, HB pencil, eraser. Check your tree against mine. /A 11 0 R endobj /S /URI /S /URI << /Contents 4 0 R 207 0 obj <>stream /Type /Page ØÙÍá^ʳH¡§m™a|Ëõç¯4ãn®^P„ê�IŞ„ı¸®/s•N;1ofC º™€wVM+ñçõ�ıKõAe§Oò6Ç�™ƒ0Ÿ.©”Ü]EßêsoÉ"›6¿WÈÂÍŒ‡Ü»™îş¿ny:ØQâî¹ìgÿkî\Àë¿äœ%8:¥–Æ‚©4óö^§f¬¸½™¡“ñìÍt“×…/XfbR& …¶%ì¢%½…endstream Check all those answers in the back of the worksheet. Double check that the leaf probabilities add to one. << Añã§%¬)eAëw2ëŠuñWFHseb‘ ¼&±”)KüuÉÑä®ùÒÑ ÷î¬zúÀk°éϽ8eA‚; endstream endobj startxref 7. a. endobj /F1 7 0 R b. << >> endobj h�ԗKo�6�����!�ޒ��Iڠ�A� v9����G0�E���$-ʲg٢HQ����Rh�����B;��� V(oQㄎ 10 0 obj ^ğ¢Úë�Rìõ:‹«šL-:×yáã´Na?>ëQâÅ>8 pœ_(g½~;Ÿç”Úª�ÁË"hœqSy±æm. endobj endobj %%EOF /H /I /Length 15 0 R 5. Tracing paper may be used. ~�F�؇����U�o��2������U���v�%���������ޛ�vP]��U��V7�Mu����¹H:�BB���i����w�ݺ���q�n6ߓ�Y�i@A���]\mWϿܓ��ߵ��ku�ݭ�u}" >> 9 0 obj Finding Probability Using Tree Diagrams and Outcome Tables Chapter 4.5 –Introduction to Probability PDF created with pdfFactory Pro trial version www.pdffactory.com. %PDF-1.5 %���� Displaying top 8 worksheets found for - Probability Tree Diagrams. >> In a conditional probability an outcome or event E is dependent upon another outcome or event F. A box contains 3 blue blocks and 2 yellow blocks. What is the probability that they end up with two boys? Conditional Probability and Tree Diagrams De nition If A and B are events in a sample space S, with P(B) 6= 0, the conditional probability that an event A will occur, given that the event B has occurred is given by P A B = P(A\B) P(B): If the outcomes of S are equally likely, then P A B = 2. h�b```�Df�e���af`a�pbP�`0WXðY������s20�[i f�x���`!oc� ��b`�LҌ@�������q\��������� � h� 2. << SMART notebook lesson. /MediaBox [0 0 792 612] 193 0 obj <> endobj /Type /Annot 4. (The trees are provided between the questions and the answers.) 3. stream RV�f�=]n^V���]߮? Instructions Use black ink or ball-point pen. << /Resources 3. 11 0 obj 0 Represent the sample space for this problem by a tree diagram. /URI (http://www.pdffactory.com) Worksheet containing the examples. A couple plans to have two children. Congratulate self. e|u������{뷻귴�����N\8Y�������ۼT����f����n��_�L9������I#�s�ݗ�{��~����rt����?��)�Ia��9����D��0 �4 �AflQ�Fߒ�'�Q��6R�!�����A�X�X|F]m�0�y�;�'~h!�SS,�E�� �cn��l��czf}��@M�������BkI��֥�qE|�� �5�� -ɍ�v=�V)@Gش�z �1��.�}�8�Ҡ���;f��?�7�+i.�)% Tree Diagrams n if you flip a coin twice, you can model the possible outcomes using a tree diagram or an /Annots 9 0 R 6 0 obj /Font /Filter /FlateDecode 12 0 obj Some of the worksheets for this concept are Kuta software probability, Tree diagrams 70b, Awork aboutprobabilitytreediagrams, Tree diagrams and probability, Mathematics linear 1ma0 probability tree diagrams, Tree diagrams and the fundamental counting principle, Wjec mathematics, Probability tree diagrams. 199 0 obj <>/Filter/FlateDecode/ID[<7A5A2F2C6F86A14C9564B82DF3B46C77><9CE1FBB2A2C54649A07B0F4D1A8497C9>]/Index[193 15]/Info 192 0 R/Length 53/Prev 21743/Root 194 0 R/Size 208/Type/XRef/W[1 2 1]>>stream << 8. >> >> 13 0 obj The tree diagram for randomly picking three blocks without replacement, with associated probabilities, would look like this: B B= B Y Y1 Y Y B3 B Y B1 endobj /Subtype /Link /Rect [262.08 22.86 367.44 9.06] Math 130 Worksheet 8 Using Tree Diagrams Names _____ 1. >> Resources included: 1. /Border [0 0 0] 5 0 obj c. Draw a probability tree diagram. H‰VÛn1}ç+汕Šc{½^ïkERT)RÕğ$BÄ%‚%¨ß™±½x/lò�{f||æâ±Üƒ$üıJg°r%a;¢Aî`3*” £‡‘‚W@í=J²*´¤é~ÎF7w h�bbd``b`� �SA�+ �� $Xw�ϖL�@#n�?#�/� n� [10 0 R 12 0 R] /Type /Annot >> /Parent 3 0 R endstream endobj 194 0 obj <>/Metadata 13 0 R/Outlines 24 0 R/PageLayout/OneColumn/Pages 191 0 R/StructTreeRoot 27 0 R/Type/Catalog>> endobj 195 0 obj <>/Font<>>>/Rotate 0/StructParents 0/Type/Page>> endobj 196 0 obj <>stream
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